HACKERRANK SOLUTIONS: JAVA IF-ELSE

Task:
In this challenge, we have to test our knowledge on if-else conditional statement and perform the following conditional actions

i. If n is odd, print Weird.

ii. If n is even and in inclusive range of 2 to 5, print Not Weird.

iii. If n is even and in inclusive range of 6 to 20, print Weird.

iv. If n is even and greater than 20, print Not Weird.

Sample Input:

3

Sample Output;

Weird

Quick bits:

• Stdin: Standard Input
• Stdout: Standard Output
• Imports: java.util.*; (or) java.util.Scanner;
• Conditional statement: If-else
• Syntax: If(condition)

                  {

                      ...........

                      ...........

                  }

             else

                  {

                      ...........

                      ...........

                  }

Solution:

import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;
public class Solution {
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
int n=sc.nextInt();            
String ans="";
if(n%2==1){
ans = "Weird";
}
else{
         

                if(n%2==0)
                {
                if(n>2 && n<5)
                    {
                    ans="Not Weird";
                }
                if(n>6 && n<=20)
                    {
                    ans= "Weird";
                }
                if(n>20)
                    {
                    ans="Not Weird";
                }
            }
              
                
            }
                
            
            System.out.println(ans);
            
        }
    }

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Hackerrank solutions: Java Stdin and Stdout

Task: In this challenge, we must read 3 integers as inputs and then print them to stdout. Each integer should be printed on a new line.

Sample Input: 

43
54
123

Sample Output:

43
54
123

Quick Bits:

Stdin: Standard Input 
Stdout: Standard Output
Imports: java.util.*; (or)  java.util.Scanner;
Using Scanner: Scanner scan = new Scanner(System.in);

Solution:

import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;
public class Solution {
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
int n=sc.nextInt();            
String ans="";
if(n%2==1){
ans = "Weird";
}
else{
         

                if(n%2==0)
                {
                if(n>2 && n<5)
                    {
                    ans="Not Weird";
                }
                if(n>6 && n<=20)
                    {
                    ans= "Weird";
                }
                if(n>20)
                    {
                    ans="Not Weird";
                }
            }
              
                
            }
                
            
            System.out.println(ans);
            
        }
    }

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Hackerrank solutions: Welcome to Java!

Input: There is no input to be given in the program below.

Output: We must print the following to output lines

1. Print Hello, World. on the first line.

2. Print Hello, Java. on the second line.

Note 1: In order to print something as an output in java we use  System.out.println("Type text to be printed here...").

Note 2: println is used to print text on a new line.

Solution: 

  

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